Saturday, April 9, 2011

x!*y! - x! - y!

Find all possible pair(s) (x, y) of nonnegative integers such that

x!*y! - x! - y!

is a perfect square.
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2 comments:

  1. UnknownApril 9, 2011 at 9:35 AM

    I reckon I've solved it. There are the zero solutions where x=y, and also x,y = 2,3. Here is my work:
    http://tumblr.com/xs921wzwh4

    ReplyDelete
  2. UnknownApril 9, 2011 at 9:57 AM

    Updated link:
    http://www.twitpic.com/4it1iq

    ReplyDelete

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