Wednesday, April 20, 2011

The five fives problem

Please complete the list: (only the digit 5 is allowed)

1 =
2 =
3 = ((55 / 5) - 5) * .5
4 = (5 / (5 / 5)) - (5 / 5)
5 = 5 / (55 / 55)
6 = (5 - (5 / 5) - (5 / 5)) !
7 = 5 + 5/5 + 5/5
8 = (5 + (55 / 5)) * .5
9 =
10 = ((5 !) / (5 + (5 / 5))) * .5
11 =
12 =
13 = ((5 !) / 5) - (55 / 5)
14 = 5 + 5 + 5 - (5 / 5)
15 = .5 * (5 + 5/5) * 5
16 = 5 + 5 + 5 + (5 / 5)
17 =
18 =
19 = ((5 !) / 5) - (5 / .5) + 5
20 =
21 =
22 =
23 = ((5 - (5 / 5)) !) - (5 / 5)
24 = 5 * 5 - (5/5)^5
25 = (5 / .5) + (5 / .5) + 5
26 = 5 * 5 + (5/5)^5
27 =
28 =
29 = ((5 !) / 5) + (5 / .5) - 5
30 = ((55/5) - 5) * 5
31 =
32 = ((5/5) + (5/5))^5
33 =
34 = ((5 - (5 / 5)) !) + (5 / .5)
35 =
36 =
37 = (((5 + 5) / 5)^5) + 5
38 =
39 = ((5 !) / 5) + (5 / .5) + 5
40 =
41 =
42 =
43 = ((5 !)/5) + ((5 !)/5) - 5
44 = 55 - (55 / 5)
45 = 5 * (5 + 5 - (5 / 5))
46 =
47 =
48 =
49 = (.5 * (5 !)) - (55 / 5)
50 =
51 =
52 =
53 = ((5!)/5) + ((5!)/5) + 5
54 =
55 =
56 =
57 =
58 =
59 =
60 = (5 !) / ((5 / 5) + (5 / 5))
61 =
62 =
63 =
64 =
65 =
66 = (55 / 5) + 55
67 =
68 =
69 =
70 =
71 = (.5 * (5 !)) + (55 / 5)
72 =
73 =
74 =
75 =
76 =
77 =
78 =
79 =
80 = 5 * (5 + (55 / 5))
81 =
82 =
83 =
84 =
85 =
86 =
87 =
88 =
89 =
90 =
91 =
92 =
93 =
94 =
95 =
96 = (((5 !) / .5) + ((5 !) / .5)) / 5
97 =
98 =
99 =
100 = 5 * (5 - (5 / 5)) * 5
101 =
102 =
103 =
104 =
105 =
106 = (555 / 5) - 5
107 =
108 =
109 =
110 =
111 =
112 =
113 =
114 =
115 =
116 = (555 / 5) + 5
117 =
118 =
119 =
120 = (5 + (5 / 5) - (5 / 5)) !
121 =
122 =
123 =
124 =
125 =
126 =
127 =
128 =
129 =
130 = ((5^5) / (5 * 5)) + 5
131 =
132 =
133 =
134 =
135 =
136 =
137 =
138 =

139 = ((((5 + (5/5)))!/5) - 5)
140 = (.5*(5 + (5*55)))
141 = ((5)! + ((5 + (5 +.5))/.5))
142 = ((5)! + ((55/.5)/5))
143 = ((((5 + (5/5)))! - 5)/5)
144 = ((((55/5) - 5))!/5)
145 = ((5*(5 + (5*5))) - 5)
146 = ((5)! + ((5/5) + (5*5)))
147 = ((5)! + ((.5*55) - .5))
148 = ((5)! + (.5 + (.5*55)))
149 = (5 + (((5 + (5/5)))!/5))

42 comments:

  1. 13 can also be 5! Divided by 5+5+.5+.5

    ReplyDelete
  2. This comment has been removed by the author.

    ReplyDelete