Fun with num3ers
Tuesday, April 19, 2011
Beyond Erdos conjecture
Brocard's Problem:
n! + 1 = m^2
Erdos conjectured that (5,4),(11,5),(71,7) are the only 3 pairs.
Now, I ask : how many solutions to
n! = x^2 + y^2
are there?
0!, 1!, 2! and 6! can be written as sum of two perfect squares. Any others?
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