Coin A: "2/3 - 1/3" that is to say, it has a 2/3 chance of landing Heads and a 1/3 chance of landing Tails.
Coin B: "1/4 - 3/4"
Coin B: "1/4 - 3/4"
The first coin tossed is Coin A.
What is the probability that you see two heads in a row before you see two tails in a row?
What is the probability that you see two heads in a row before you see two tails in a row?
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ReplyDelete44/180
ReplyDeleteIs that right?
Actually, the answer is 13/33.
ReplyDeleteWould you like the details of the solution?
Bonus question: Find a generalization, where coin A "p - (1-p)" and coin B "q - (1-q)" with p > q
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