Sunday, April 17, 2011

Tossing 2 biased coins

2 coins : coin A and coin B.

Coin A: "2/3 - 1/3" that is to say, it has a 2/3 chance of landing Heads and a 1/3 chance of landing Tails.
Coin B: "1/4 - 3/4"

The first coin tossed is Coin A.

What is the probability that you see two heads in a row before you see two tails in a row?


  1. This comment has been removed by the author.

  2. Actually, the answer is 13/33.
    Would you like the details of the solution?

  3. Bonus question: Find a generalization, where coin A "p - (1-p)" and coin B "q - (1-q)" with p > q