Friday, April 15, 2011

1^2 + 2^2 + 3^2 + ... + n^2

Find a positive integer n > 1 such that

1^2 + 2^2 + 3^2 + ... + n^2

is a square number.

2 comments:

  1. n would be 24, giving a total of 4900 or 70^2.

    Paul.

    ReplyDelete
  2. True. Could you prove that the solution is unique?

    ReplyDelete