Friday, April 15, 2011

1^2 + 2^2 + 3^2 + ... + n^2

Find a positive integer n > 1 such that

1^2 + 2^2 + 3^2 + ... + n^2

is a square number.
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2 comments:

  1. PaulApril 15, 2011 at 3:51 AM

    n would be 24, giving a total of 4900 or 70^2.

    Paul.

    ReplyDelete
  2. BenVitaleApril 15, 2011 at 10:12 AM

    True. Could you prove that the solution is unique?

    ReplyDelete

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