Fun with num3ers
Saturday, January 22, 2011
Palindromic numbers n(n + a)
To find
n
such that
n(n + a)
is a Palindromic number
a = 1, 2, 3, 4, 5, 6, 7, 8, 9
n(n + 1)
n(n + 2)
n(n + 3)
n(n + 4)
n(n + 5)
... 814 * (814 + 5) = 666666.
n(n + 6)
n(n + 7)
n(n + 8)
n(n + 9)
n(n + 20)
... 23 * (23 + 20) = 989
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