Fun with num3ers
Sunday, November 28, 2010
Divisibility problem
x and y are integers, such that
x > 1, y > 1
For all n > 0, (x^n - 1) is divisible by (y^n - 1)
Show that x = y^k, with k being a positive integer.
No comments:
Post a Comment
Newer Post
Older Post
Home
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment