Yes, there are 5 distinct solutions. If m and n are the roots of the equation, we can write: (x - m)(x - n) = 0 Or x^2 - (m + n)x + m*n = 0 So, m + n = 48 <=> m = 48 - n We consider the primes as values for p and see if 48 - p is also prime. We end up with 5 solutions.
5 five
ReplyDelete215
287
407
527
551
solution is easy: p1*p2=k and p1+p2=48
just search in the 14 first primes less/equal 43
Yes, there are 5 distinct solutions.
ReplyDeleteIf m and n are the roots of the equation, we can write: (x - m)(x - n) = 0
Or x^2 - (m + n)x + m*n = 0
So, m + n = 48 <=> m = 48 - n
We consider the primes as values for p and see if 48 - p is also prime. We end up with 5 solutions.