Yes, there are 5 distinct solutions. If m and n are the roots of the equation, we can write: (x - m)(x - n) = 0 Or x^2 - (m + n)x + m*n = 0 So, m + n = 48 <=> m = 48 - n We consider the primes as values for p and see if 48 - p is also prime. We end up with 5 solutions.

5 five

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solution is easy: p1*p2=k and p1+p2=48

just search in the 14 first primes less/equal 43

Yes, there are 5 distinct solutions.

ReplyDeleteIf m and n are the roots of the equation, we can write: (x - m)(x - n) = 0

Or x^2 - (m + n)x + m*n = 0

So, m + n = 48 <=> m = 48 - n

We consider the primes as values for p and see if 48 - p is also prime. We end up with 5 solutions.